Return five first digits out of a random number

[dev123]

How can I get the first 5 digits in a random length integer?

For example: users input 1234567, 123456789, 1012345671

I should get 12345, 12345, 10123 respectively.
The number input by an user is not known in advance.

[qwertylurker]

Keep dividing the number by 10 until you get something <= 99999.

[dwks]

If you're fairly sure that the user will enter numbers sensibly and not with e.g. leading spaces, you could just read the input as a string and get the first five characters. That's a bit of a hack though and so I also echo qwertylurker's suggestion.

while(n >= 100000) n /= 10;

[dev123]

Ok, thanks for the tip qwertylurker and dwks.